(5/x+3)+(1/x-2)=(8/(x^2)+x-6)

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Solution for (5/x+3)+(1/x-2)=(8/(x^2)+x-6) equation: 



(5/x+3)+(1/x-2)=(8/(x^2)+x-6)

We move all terms to the left:

(5/x+3)+(1/x-2)-((8/(x^2)+x-6))=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x^2+x-6))!=0

x∈R



We get rid of parentheses

5/x+1/x-((8/x^2+x-6))+3-2=0

We calculate fractions

We do not support expression: x^3

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